A stepladder of negligible weight is constructed as shown in the figure below, w

Question

A stepladder of negligible weight is constructed as shown in the figure below, with AC = BC = l. A painter of mass m stands on the ladder a distance d from the bottom. Assume the floor is frictionless. Suggestion: Treat the ladder as a single object, but also treat each half of the ladder separately. Find the tension (T) in the horizontal bar DE connecting the two halves of the ladder. (Use any variable or symbol stated above as necessary.) T = Find the normal forces at A and B. (Use any variable or symbol stated above as necessary.) nA = nB =

Explanation / Answer

A relevant method to solve this question is as follows: To find normal force: Fn = (1.2 * 10^3) (9.81) = 11772 N To find acceleration: d = 0.5 (Vi + Vf) * time 35 = 0.5 (45 + 0) * time 35 = 0.5 (45) * time 35 = 22.5 * time 35/22.5 = time time = 1.6 seconds acceleration = (Vf - Vi) / time = (0 - 45) / 1.6 = -28.12 m/s^2 To find force using Newtons' law: F= (1.2*10^3)(.28.12) = -33744 N u (coefficient of friction) = -33744 / 11772 = -2.87 For tension force mg - T = ma T = m(g-a) since the monkey is hang in stationary,velocity=0, acceleration= 0 therefore,tension T = mg

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