In an engine, a piston oscillates with simple harmonic motion so that its positi

Question

In an engine, a piston oscillates with simple harmonic motion so that its position varies according to the expression, x = 4.00 cos (t +?/5) where x is in centimeters and t is in seconds. (a) At t = 0, find the position of the piston. . We are given x as a function of time. For any x(t) you can determine the position at a particular time by putting that value into the function. cm (b) At t = 0, find velocity of the piston. cm/s (c) At t = 0, find acceleration of the piston. cm/s2 (d) Find the period and amplitude of the motion. period s amplitude cm

Explanation / Answer

a)t = 0 => x(t) = 4*cos((22/7)/5) = 3.235473276 cm b)t = 0 => v = -4*sin((22/7)/5) = -2.351959329 cm/s c)t = 0 => a = -4*cos((22/7)/5) = -3.235473276 cm/s^2 d)Period = 2pi/w = 2pi/1 = 2pi seconds Amplitude = 4 cm.

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.