A 0.580-kg object attached to a spring with a force constant of 8.00 N/m vibrate

Question

A 0.580-kg object attached to a spring with a force constant of 8.00 N/m vibrates in simple harmonic motion with an amplitude of 11.2 cm. (a) Calculate the maximum value of its speed. _________________cm/s (b) Calculate the maximum value of its acceleration. ________________cm/s2 (c) Calculate the value of its speed when the object is 7.20 cm from the equilibrium position. _______________cm/s (d) Calculate the value of its acceleration when the object is 7.20 cm from the equilibrium position. __________________cm/s2 (e) Calculate the time interval required for the object to move from x = 0 to x = 5.20 cm. ____________________s

Explanation / Answer

a) 1/2 x k x A2 = 1/2 x m x v2max

1/2 x 8 x 0.1122 = 1/2 x .580 x v2max

vmax = 0.41 m/s = 41 cm/s

b) max aceeleration = k x A

= 8 x 0.112

= 0.896 m/s2

= 89.6 cm/s2

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