Find the rotational inertia of the system of point particles shownin the figure

Question

Find the rotational inertia of the system of point particles shownin the figure assuming the system rotates about the a) x-axis, b)y-axis, c) z-axis. The z-axis is perpendicular to thexy-plane and points out of the page. Point particle A hasmass of 200 g and is located (x, y, z) = (-3.0 cm, 5.0 cm, 0),point particle B has a mass of 300 g and is at (6.0 cm, 0, 0), andpoint particle C has a mass of 500 g and is at (-5.0 cm, -4.0 cm,0). d) What are the x-and y-coordinates of the center of massof the system?

Explanation / Answer

Ix=200*5^2+300*0+500*4^2=13000 g cm^2 Iy=200*3^2+300*6^2+500*5^2=25100 g cm^2 Iz=200*34+300*6^2+500*41=38100 g cm^2 Xcm=200*(-3)+300*6+500*(-5)/1000=-1.3 ycm=200*5+300*0+500*0/1000=1

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