A spring lies on a horizontal table, and the left end of the spring is attached

Question

A spring lies on a horizontal table, and the left end of the spring is attached to a wall. The other end is connected to a box. The box is pulled to the right, stretching the spring. Static friction exists between the box and the table, so when the spring is stretched only by a small amount and the box is released, the box does not move. The mass of the box is 0.60 kg, and the spring has a spring constant of 79 N/m. The coefficient of static friction between the box and the table on which it rests is ?s = 0.60. How far can the spring be stretched from its unstrained position without the box moving when it is released?

Explanation / Answer

Max stretching force = Max. static friction force kx = mu. R mu = coefff of friction R = reaction = mg Therefore x = mu. mg / k = (0.60 x 0.60 x 9.8)/79 meters =0.044m

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