The solar wind is a thin, hot gas given off by the sun. Charged particles in thi

Question

The solar wind is a thin, hot gas given off by the sun. Charged particles in this gas enter the magnetic field of the earth and can experience a magnetic force. Suppose a charged particle traveling with a speed of 7.40 106 m/s encounters the earth's magnetic field at an altitude where the field has a magnitude of 1.10 10-7 T. Assuming that the particle's velocity is perpendicular to the magnetic field, find the radius of the circular path on which the particle would move if it were each of the following.

Explanation / Answer

r = mv/qB = 6.73*10^13*(m/q) As you have not specified the the particles, i have answered it with mass and charge as vaiables, So, if the particle is an electron , then plug the mass of electron in 'm' and charge of electron in 'q' in the equation and thus you will get the answer. you can do the same with other particles also.... ______________HOPE THIS HELPS________________

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