At the local swimming hole, a favorite trick is to run horizontally off a cliff

Question

At the local swimming hole, a favorite trick is to run horizontally off a cliff that is 7.34 m above the water. One diver runs off the edge of the cliff, tucks into a "ball," and rotates on the way down with an average angular speed of 2.38 rev/s. Ignore air resistance and determine the number of revolutions she makes while on the way down

Explanation / Answer

initial velocity is o .. i.e., u=0, s=7.34m, a=g=9.8m/s^2..... from equations of motion we have s=ut+1/2at^2.... substituting the given values we get 7.34=1/2*9.8*t^2.....................=>t^2=7.34/4.9=1.4979...........=>t=(1.4979)^1/2=1.224 sec. angular velocity=2.34 rev/sec....... so no. of revolutions made =2.34*1.224=2.87 revolutions are made..................so nearly 3 revolutions are made....................................... ..........................................................PLEASE RATE THE ANSWER

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.