A candle is placed in front of a convex mirror. http://session.masteringphysics.
ID: 2199934 • Letter: A
Question
A candle is placed in front of a convex mirror.http://session.masteringphysics.com/problemAsset/1011665/19/1011665A.jpg (Part A)
(1) Consider the following diagrams, where C and F represent the center of curvature and the focal point of the convex mirror, respectively. In these diagrams, the image formed by the mirror is obtained using the ray tracing technique. Which diagram(s) are correct? (Part A figure)
(2) If the radius of curvature of the convex mirror is 50.0 cm , at what distance d0 from the mirror must the candle be placed so that its image is formed 20 cm from the mirror?
Express your answer in centimeters.
d0=cm
The convex mirror is now replaced by a concave mirror with the same radius of curvature.
(Part C) http://session.masteringphysics.com/problemAsset/1011665/19/1011665_02.jpg
(1) Consider the following diagrams, where now C and F represent, respectively, the center of curvature and the focal point of the concave mirror. Again, the image formed by the mirror is found by ray tracing. Choose the correct diagram(s). (Part C figure)
(2) Assuming that the candle remains at a distance d0 from the mirror (the same distance found in Part B), at what distance d1 from the mirror will its image form now?
Express your answer in centimeters.
d1=cm
Explanation / Answer
The mirror formula is given by 1/f = 1/u + 1/v where f - focal length (also 1/2 of the radius of curvature) u - object distance v - image distance Q1: f = -25 cm (convex mirror has negative focal length) v = - 20 cm (negative because image is virtual) u = d0 Substituting in the formula, -1/25 = 1/d0 - 1/20 1/d0 = -1/25 + 1/20 = 1/100 d0 = +100 cm Q2: f = +25 cm v = d1 u = d0 = +100 cm Substituting in the formula, 1/25 = 1/100 + 1/d1 1/d1 = 3/100 d1 = +33.33 cm
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