A person bounces up and down on a trampoline, while always staying in contact wi

Question

A person bounces up and down on a trampoline, while always staying in contact with it. The motion is simple harmonic motion, and it takes 1.57 s to complete one cycle. The height of each bounce above the equilibrium position is 42.7 cm. Determine (a) the amplitude and (b) the angular frequency of the motion. (c) What is the maximum speed attained by the person?

Explanation / Answer

(a) the amlitude is 42.7 cm (b) one round takes 1.57 second --> the frequency is 0.637 HZ --> angular frequency is 2*pi*f= 4 rad sec (c)usae conservation of energy.. all potential energy is transformed to the kinetic energy --> mgh=mv^2/2 --> v=sqrt(2gh)=2.89 m/sec

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