The horizontal beam in the figure below (Figure 1) weighs 190 , and its center o
ID: 2204758 • Letter: T
Question
The horizontal beam in the figure below (Figure 1) weighs 190 , and its center of gravity is at its center. a) Find the tension in the cable. b) Find the horizontal component of the force exerted on the beam at the wall. c) Find the vertical component of the force exerted on the beam at the wall.
The horizontal beam in the figure below (Figure 1) weighs 190 , and its center of gravity is at its center. a) Find the tension in the cable. b) Find the horizontal component of the force exerted on the beam at the wall. c) Find the vertical component of the force exerted on the beam at the wall.Explanation / Answer
take moments about the hinge on the wall
(2 x 190) + (4 x 300) - (4 x TsinA) = 0
T = tension
A = angle between beam and cable
sinA = 3/5
380 + 1200 - (12/5)T = 0
1580 = (12/5)T
7900 = 12T
T = 658.33 N
-----------------------------------------
The only other horizontal force on the beam is from the cable.
In equilibrium
force at wall = Hor. force in cable
Horizontal force = Horizontal component of T = TcosA
cosA = 4/5
Horizontal force = 658.33 x 4/5
= 526.66 N
------------------------------------------------
In equilibrium:
sum of vertical forces = 0
300 + 190 - TsinA - Y = 0
490 - (658.33 x 3/5) - Y = 0
490 - 394.88 = Y
Y = 95 N
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.