The projection lens in a certain slide projector is a single thin lens. A slide

Question

The projection lens in a certain slide projector is a single thin lens. A slide 24.1 mm high is to be projected so that its image fills a screen 1.71 m high. The slide-to-screen distance is 2.92 m. (a) Determine the focal length of the projection lens. 1 mm (b) How far from the slide should the lens of the projector be placed to form the image on the screen? 2 mm

Explanation / Answer

u=distanc btween lens nd slide v=distanc btween lens nd screen AB=hight of slide CD=hight of screen givn dat u+v=29.5m ->(1) now by magnification farmula of lens, CD/AB=-v/u => -v/u=1.83/(24.1*10^-3) => v=-75.93u ->(2) now puting it in (1), u-75.93u=2.95 => u=-0.0393 m nd by (2) v=2.989 or 3 m now by lens formula, 1/F=1/u+1/v we get F=-0.0398 m - sign means lens is convex so, (a) focal lenght=39.8 mm (b) distance between lens nd slide=39.3 mm hope this will help u. :)

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