In each of the cases that follow, the components of a vector A are given. Use tr

Question

In each of the cases that follow, the components of a vector A are given. Use trigonometry to find the magnitude of that vector and the counterclockwise angle it makes with the + axis.. Ax= 6.00 m/s, Ay= -17.0 m/s Please give your answer in the interval [0,360]degrees

Explanation / Answer

CONCEPT: If a vector of magnitude 'r' makes and angle 'a' with x-axis, then its x-component = (r)*Cos(a) and y-component = (r)*Sin(a) a) Angle 45 deg and magnitude = 47 N ==> x = 47*Cos(45) N = 33.2337 N and y = 47*Sin(45) N = 33.2337 N b) 5pie/6 rad = 5 x 180/6 = 150 deg; cos(150) = cos(180-30) = -cos(30) and sin150 = sin(30) ==> x = -68Cos(30) m/s = -58.888 m/s and y = 68Sin(30) = 34 m/s c) Cos325 = Cos(360 - 35) = Cos(35) and Sin(325) = Sin(360 - 35) = -Sin(35) ==> x = (258)*Cos(35) lbs and y = -(258)*Sin(35) lbs d) 1.4pi = 1.4 x 180 = 252 deg. Cos(252) = -Cos(72) and Sin(252) = -Sin(72) ==> x = -(70)*Cos(72) km and y = -(70)*Sin(72) km ['c' and 'd' values may be evaluated at your end].

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