A sled starts from rest at the top of a hill and slides down with a constant acc

Question

A sled starts from rest at the top of a hill and slides down with a constant acceleration. At some later time it is 14.4 m from the top; 2.00 s after that it is 25.6 m from the top, 2.00 s later 40.0 m from the top, and 2.00s later it is 57.6 m from the top.

a. What is the acceleration of the sled?

b. What is the speed of the sled when it passes the 14.4-m point?

c. How much time did it take to go from the top to the 14.4-m point?

d. How far did the sled go during the first second after passing the 14.4-m point?

Explanation / Answer

after interval of 2s after the sled passedthe point14.4 m from the top 14.4 m DS=40-14.4=25.6, DT=2s average velocity=25.6/2=12.8m/s, as acceleration is constant, this average velocity is the instantaneous velocit at the middle of the interva Next interval of 2 s: DS=57.6-40=17.6m,DT=2s AV.vel=17.6/2=8.8m/s.This is the velocity at the middle of this second interval (of2s). Note: something wrong with theenunciation.I n the cosecutive intervals of 2s, theaverage veland the distance covered should go on increasing .But here, DS and av.vel have decreased in the second interval of 2s. So I suspect an error in typing, probably.

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.