To practice Problem-Solving Strategy 10.1 for conservation of mechanical energy

Question

To practice Problem-Solving Strategy 10.1 for conservation of mechanical energy problems. Tarzan, in one tree, sights Jane in another tree. He grabs the end of a vine with length 20 m m that makes an angle of 45^circ with the vertical, steps off his tree limb, and swings down and then up to Jane?s open arms. When he arrives, his vine makes an angle of 30^circ with the vertical. Determine whether he gives her a tender embrace or knocks her off her limb by calculating Tarzan?s speed just before he reaches Jane. You can ignore air resistance and the mass of the vine. What is Tarzan?s speed v_{ m f} just before he reaches Jane? Iknow it's 7.9 but the other part I have no Idea " You can check if your work makes sense by comparing your results with the results that you obtain using the kinematics equations for free fall. What vertical distance Deltay does a free-falling particle travel from the moment it starts to the moment it reaches a speed of 7.9 m m/s if it starts from rest? Work out your solution using one of the equations for vertical motion with constant acceleration, specifically, v_{ m f}^2=v_{ m i}^2 + 2aDelta y, where v_{ m i} and v_{ m f} are the particle?s initial and final speeds, respectively, and a is the particle?s acceleration. "

Explanation / Answer

1) B

2)

---> 9.8*20*(co30-cos45) = 0.5*V^2

v = 7.89 m/s

3) and i have done this question so C will be 3.2m using the equation they give you

v2f=v2i+2a?y", so 7.2^2= 0^2+2(9.8)(y-y_0)

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