(a) If 1 mol of a gas in a container occupies a volume of 14 L at a pressure of

Question

(a) If 1 mol of a gas in a container occupies a volume of 14 L at a pressure of 1 atm, what is the temperature of the gas in kelvins?
(No Response) K

(b) The container is fitted with a piston so that the volume can change. When the gas is heated at constant pressure, it expands to a volume of 25 L. What is the temperature of the gas in kelvins?
(No Response) K

(c) The volume is fixed at 25 L, and the gas is heated at constant volume until its temperature is 355 K. What is the pressure of the gas?
(No Response) atm

Explanation / Answer

(a) Using pV = nRuT, (1.01325*105)*(14*10-3) = 1*8.314*T

This gives T = 170.6 K

(b) For constant pressure process, V1/T1 = V2/T2

So, T2 = (25/14)*170.6 = 304.7 K

(c) For constant voulme process, P1/T1 = P2/T2

So, P2 = (355/304.7)*1 = 1.165 atm

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