A piece of iron weighing 200g at 120oC and a piece of copper weighing 150g at -5

Question

A piece of iron weighing 200g at 120oC and a piece of copper weighing 150g at -50oC are both dropped into an insulated beaker containing ethyl alcohol at 20oC. Determine the final temperature of the system. (take specific heat of alcohol to be 2400 J/kg.K and specific heat of iron and copper to be 449 J/kg.K and 385 J/kg.K respectively) I understand setting them equal to each other for 2 items but how do I deal with the alcohol? I guess my question is how do I know if the final temp is between the -50 and 20 or 20 and 120? I.E. (50-t)+(20-t)=(120-t) or (50-t)= (20-t)+(120-t), if my confusion makes sence. I was using k=(q*l)/(A*dt)

Explanation / Answer

Final temperature of a system??? Assume we have a sample of 2 kg of aluminum at 50 degrees C that we put in contact with 4 kg of copper at 0 degrees C. If we assume they are perfectly insulated except for the point of contact what is the final temperature of the system? ans You need to know the specific heat capacity of both aluminium and copper. specific heat capacity of copper = 400 J kg^-1 K^-1 specific heat capacity of aluminium = 900 J kg^-1 K^-1 Let the final temperature be T degree C. then 0

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.