#36 Two express trains started 5 minutes apart. Starting from rest, each is capa

Question

#36 Two express trains started 5 minutes apart. Starting from rest, each is capable of a maximum speed of 160km/h after uniformly accelerating over a distance of 2.0 km. What is the acceleration of each train? How far ahead is the first train when the second one starts? How far apart are they when they are both traveling at maximum speed

Explanation / Answer

v^2 =u^2+2*a*s [u=0, s= 2000,v= 160*1000/3600=44.44 m/sec] =>a =0.49 m/sec^2 s= ut+0.5*at^2 [ u=0] =>s=22.05 km time taken to attain the constant speed v=0.49*t =>t= 44.44/0.49=90.69 sec so first train travells for 390.69 sec s= 0.5*0.49*390.69^2 =37.396 km for secons train s= 0.5*0.49*90.69^2 =2.015 km distance b/w trains = 37.396-2.015 =35.381 km

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