An automobile has a mass of 1840 kg and a velocity of 15.0 m/s. It makes a rear-

Question

An automobile has a mass of 1840 kg and a velocity of 15.0 m/s. It makes a rear-end collision with a stationary car whose mass is 2110 kg. The cars lock bumpers and skid off together with the wheels locked. (a) What is the velocity of the two cars just after the collision? (b) Find the impulse that acts on the skidding cars from just after the collision until they come to a halt. (c) If the coefficient of kinetic friction between the wheels of the cars and the pavement is ?k = 0.565, determine how far the cars skid before coming to rest. I know that the answer to A is 6.876 and the answer to C is 4.4 I can't figure out part B

Explanation / Answer

for number 2: centripetal force= mass times centripetal acceleration. to find C.A. square the velocity and divide by the radius. so 1460 times 15 times 15 and then divide by 25 and whatever that is that's the answer. for number 1 I'll see if I can find anything...sorry ok I got the formulas for number one are v1=m1-m2 divide it by the sum of the masses times the velocity the answer is -2.62 m/s for the other object the formula is 2 times m1 divide it by the sums of the masses times the velocity and it confirms that it is 2.38 v1= (.250-.800/.250+.800) all this times 5. = -2.62m/s. I just realized that the answer for number one is even easier you don't have to even do any work. Since linear momentum is conserve the final velocity should add to 5. so 5 minus 2.38 and that give the answer with a negative sign because it goes in the other direction.

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