A o.140 kg baseball in the x-direction with a velocity of 26.6 i. It is struck b

Question

A o.140 kg baseball in the x-direction with a velocity of 26.6 i. It is struck by a bat and is popped straight up at 35.0 m/s j. a. what was the impulse (in unit vector notation) delivered to the ball in its collision with the bat? b. If the ball and bat were in contact for 0.01 s, what was the average force (in unit vector notation) of the bat on the ball during the collision? c. Using conservation of mechanical energy and not kinematics, how high above the point it hits the bat does the ball go?

Explanation / Answer

F = 140*26.6/.01 = 372400N by consevation of energy: 140*g*h = .5*140*35^2 h = 61.25m high ball will rise

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