1) A two Truck is dragging a stalled car of mass 1000 kg a distance of 0.5 km. T

Question

1) A two Truck is dragging a stalled car of mass 1000 kg a distance of 0.5 km. The cable makes an angle of 25 degrees with the road and the tension in the cable is 4000 N. Starting from rest and assuming no friction on the car, what is the car's velocity after traveling 0.5 km? W = change in Kinetic Energy (4000 N)cos(25)*(500 m) = [(0.5)*(1000 kg)*v^2] - [0] v^2= 3625 v= 60 m/s 2) A 500 N box is pushed across a rough, horizontal floor with a force of 250 N applied parallel to the floor. The coefficient of kinetic friction is 0.40. If the box started at rest, what would be its final velocity after being pushed a distance of 5 m. Wnet = Wpush - W friction = [(250 N)*(5 m)*cos(0)] - [(500 N)*(0.40)*(5 m)*cos(180)] = 250 J Wnet = change in Kinetic Energy 250 J = [(0.5)*(51 kg)*v^2] - [0] 500 J = (51 kg)*v^2 v= 3.13 m/s If I did these wrong could someone show where I made my mistakes. Thank You

Explanation / Answer

conservation of energy work done = change in energy 1st one is good work done = change in energy. 2nd one is also fine.

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.