In 2003, an earthquake in Japan generated waves that traveled outward at 7.0 {\

Question

In 2003, an earthquake in Japan generated waves that traveled outward at 7.0 { m km}/{ m s}. 200 { m km} to the west, seismic instruments recorded a maximum acceleration of 0.25 { m g} along the east-west axis at a frequency of 1.1 { m Hz}. a.) What was the wavelength? b.) What was the maximum horizontal displacement of the ground as the wave passed? I already found the answer to part a.) which is 6400m. I need help with part b.. Can you please show your work, explain your reasoning, and give the answer. Thank you this would be so helpful.

Explanation / Answer

a max= 0.25g x 9.8m/s ^2 = 2.45

a max = (2 x pi x f)^2 x A.

--> A = a max / (2 x pi x f)^2
= 2.45 /(2 x pi x 1.1)^2
= 0.0512 m --> Answer

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