2. In the figure above, two 2 kg masses and a 4 kg mass are suspended from a 5 m

Question

2. In the figure above, two 2 kg masses and a 4 kg mass are suspended from a 5 meter long bar (assume the bar has no mass). You want to tie a rope (indicated by the dotted line) somewhere along the bar in order to hold up the bar and keep it balanced. The distance between the 2 kg masses is 1 meter. a. Around the pivot point of the 4 kg mass, what is direction of the torque exerted by the rope? b. Around the pivot point 4 kg mass, what is the direction of the torque exerted by the closer 2 kg mass? c. Around the pivot point of the 4 kg mass, what is the direction of the torque exerted by the 2 kg mass at the far left? d. What is the tension in the rope? e. What is the distance of the rope from the 4 kg mass?

Explanation / Answer

a)clockwise b)anti clockwise c)anti clockwise d)T=8*9.81=78.48 N e)let distance of 4 kg mass from rope=x 4*g*x=2*g*(4-x)+2*g*(5-x) x=9/4=2.25 m

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