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A 50.0-kg child stands at the rim of a merry-go-round of radius 2.00 m, rotating

ID: 2213283 • Letter: A

Question

A 50.0-kg child stands at the rim of a merry-go-round of radius 2.00 m, rotating with an angular speed of 2.85 rad/s. What is the child's centripetal acceleration? m/s2 What is the minimum force between her feet and the floor of the carousel that is required to keep her in the circular path? N What minimum coefficient of static friction is required? Is the answer you found reasonable? In other words, is she likely to stay on the merry-go-round? Yes No An air puck of mass m1 = 0.28 kg is tied to a string and allowed to revolve in a circle of radius R = 1.4 m on a frictionless horizontal table. The other end of the string passes through a hole in the center of the table, and a mass of m2 = 1.4 kg is tied to it (see the figure below). The suspended mass remains in equilibrium while the puck on the tabletop revolves. What is the tension in the string? N What is the horizontal force acting on the puck? N What is the speed of the puck? ? m/s Need Help?

Explanation / Answer

a)

a = ²r

a = (2.85 rad/s)²(2.00 m)

a = 16.245 m/s²

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b)

F = ma

F = (50.0 kg)(16.245 m/s²)

F = 812.25 N

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c)

ma = mg

a = g

16.245 m/s² = (9.81 m/s²)

= 1.66

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