(a) What is the tangential acceleration of a bug on the rim of a 12.0-in.-diamet

Question

(a) What is the tangential acceleration of a bug on the rim of a 12.0-in.-diameter disk if the disk accelerates uniformly from rest to an angular speed of 76.0 rev/min in 4.50 s? m/s (b) When the disk is at its final speed, what is the tangential velocity of the bug? m/s (c) One second after the bug starts from rest, what is its tangential acceleration? m/s (d) One second after the bug starts from rest, what is its centripetal acceleration? m/s (e) One second after the bug starts from rest, what is its total acceleration? m/s

Explanation / Answer

a = ?w/?t = 76x( 2 p / 60 x 4.5) = 1.77 rad/s a = a . r = 1.77 x 0.1524 = 0.27 m/s/s b) v = w . r = 76 x 2p x 0.1524 / 60 = 1.21 m/s c) You are told the acceleration is uniform = 0.27 m/s/s d) v^2 / r = 0.27^2 / 0.1524 = 0.48 m/s e) sqrt( 0.27^2 + 0.48^2) = 0.550 m/s

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