14.23 in John Taylor\'s Classical Mechanics Solution Consider the scattering of

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Consider the scattering of a particle with energy E by a fixed, repulsive 1/(r^3) force field, with potential energy U=?/(r^2). Use the relation (14.61) from Problem 14.20 to find ? in terms of b and hence show that the differential cross section is (d?/d?)=(?/E)[((pi^2)(pi-?))/((?^2)((2pi-?)^2)sin?)]. To refresh your memory as to find r(min) you might look at Figure 8.5 (the case E>0). You should be able to solve your equation for ? in terms of b to get b in terms of ? and thence the cross section. 14.61 - ?=pi-2 times integral from r(min) to infinity of: ((b/(r^2))dr)/[(1-(b/(r^2))-U(r)/E)^1/2] Here is a pic of the problem, including Figure 14.61 and 8.5 Original problem (14.23): http://i1088.photobucket.com/albums/i337/bryandarling15/orig.jpg Figure 14.61: http://i1088.photobucket.com/albums/i337/bryandarling15/theta.jpg Figure 8.5: http://i1088.photobucket.com/albums/i337/bryandarling15/rmin.jpg

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