A + 5.0 C change is located al the origin. A -13.0 C charge is placed at x = 1.0
ID: 2215276 • Letter: A
Question
A + 5.0 C change is located al the origin. A -13.0 C charge is placed at x = 1.0 m. At what finite location(s) on the x axis will the electric field be equal to zero? in between the particles, closer to the positive particle in between the particles, closer to the negative particle not in between, but closer to the positive particle not in between, but closer to the negative particle It can never be zero. Electric field lines always point from higher potential lo lower potential. from lower potential to higher potential. in the same direction as the equipotential lines. in the opposite direction as the equipotential lines. Two long wires are parallel to each other. The wires carry currents of different magnitudes. If the amount of current in each wire is halved, the magnitude of the force between the wires will be twice the original force. four limes the original force. the same as the original force. half the original force. one fourth the original force. Two point charges are placed on two of the corners of a triangle as shown. What magnitude of force would be felt by a 6.0 mu C charge placed at the right angle? 10 N 24 N 32 N 44 N 58 NExplanation / Answer
From your scratch work, it looks like you're on the right track.
Calculate Fx and Fy using Coulomb's law. Since it's just asking for the magnitude, you don't need to do sin/cos. Just do
F = (Fx2 + Fy2)
And you have the magnitude (I got 32 btw).
Just be careful of units. You have C and cm that you need to convert to C and m first.
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