A heat engine carries 2.10 mol of an ideal monatomic gas around the cycle shown

Question

A heat engine carries 2.10 mol of an ideal monatomic gas around the cycle shown in the figure. Process 1-2 takes place at constant volume and takes the gas from 300 K to 600 K, process 2-3 is adiabatic and takes the gas from 600 K to 455 K, and process 3-1 takes place at a constant pressure and returns the gas to 300 K. Compute the heat Q for the whole cycle. Compute the change in internal energy DeltaE for the cycle as a whole. Calculate the work done by the gas for the cycle. If the initial pressure at point 1 is 4.0 atm, find the pressure at point 2 in atm. If the initial pressure at point 1 is 4.0 atm, find the volume at point 3 (in m3).

Explanation / Answer

Since figure was not uploaded i could nt solve the problem but I can give you the process to solve the above types of questions. Process 1 follows P/T = constant => P(1)/T(1) = P(2)/T(2) => P(1)/P(2) = T(1)/T(2) = 300/600 = 0.5 Process 2 follows P^(1-y)T^(y) = constant (y=gamma=1.5) solving which we get P(2)/P(3) = (600/455)^3 = 2.293 HEAT CONTENT will be area in the region = Work done in adiabatic - Work done in last process

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