A large steel box is placed on an inclined steel surface that makes an angle of

Question

A large steel box is placed on an inclined steel surface that makes an angle of 35* with the horizontal. The box has a mass of 200 kg.
static and kinetic forces -- steel on steel 0.15 and 0.09 respectively
Calculate the perpindicular force, the parallel force, and the normal force
Calculate the friction forces, both static and kinetic
Will the box start to slide down the surface as soon as it is placed on the incline or is a push needed to get started? How much?
What will the acceleration be of the box down the incline once its sliding motion has started

Explanation / Answer

Maximum static friction=smgcos=0.15*0.2*9.8*cos35=0.2408N

kinetic friction force=kmgcos=0.1445N

force due to gravity=mgsin =1.124 N

Perpendicular force is zero since the normal force is balanced by a component of gravity.

parallel force=1.124 N-0.2408N=0.883N

Yes, the box will slide down as soon as it is placed on the incline

Accleration=gsin -kgcos=4.9m/s2

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