When you throw a ball upwards, the equation of motion is x(t)=x0 +v0t +.5at^2. N

Question

When you throw a ball upwards, the equation of motion is x(t)=x0 +v0t +.5at^2. Now can someone go through the steps of motion of this ball? And can you answer these doubts below? 1) When the ball is moving up, velocity is positive and it is slowing down so acceleration is negative? 2) When the ball falls down, velocity is negative and it is speeding up so acceleration is positive? 3) The equation above it a negative parabola. What does it mean for the x values to be negative IN TERMS OF THE BALL'S POSITION?

Explanation / Answer

1) Yes, the acceleration is negative. 2) The acceleration is still negative: the acceleration will always be gravity, a=-9.8 m/s^2 3) A negative x-value means the the ball's position is lower than its initial position.

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