A small mass M attached to a string slides in a circle (x) on a frictionless hor

Question

A small mass M attached to a string slides in a circle (x) on a frictionless horizontal table, with the force F providing the necessary tension (see figure). The force is then increased slowly and then maintained constant when M travels around in circle (y). The radius of circle (x) is twice the radius of circle (y).

1.M's angular momentum at x is .... that at y.

2.While going from x to y, there is no torque on M

3.As M moves from x to y, the work done by F is .... 0.

4.M's kinetic energy at x is half that at y.

5.M's angular velocity at x is half that at y.

**answer choices are less than, greater than, equal to or true or false**

Explanation / Answer

1) angular momentum is the same, because of angular momentum conservation. And the fact that there is no torque on a mass. 2) torque is zero, because the force is perpendicular to the motion vector. 3) the work is greater than 0. work = f*d, both F and d are >0 4) 4 - true. 5) 5 - false, the velocity is sqrt(2) greater at y than at x

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.