Now add a third, negatively charged, particle, whose charge is -q2 (particle 2).

ID: 2222939 • Letter: N

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Now add a third, negatively charged, particle, whose charge is -q2 (particle 2). Particle 2 fixed on the y-axis at position (0,d2,0) what is the new net force on particle 0, from particle 1 and particle 2? Express your answer (a vector) using any or all ofk,q0,q1,q2,d1,d2,x,y and z. Particle 0 experiences a repulsion from particle 1 and an attraction toward particle 2. For certain values of d1 and d2, the repulsion and attraction should balance each other, resulting in no net force. For what ratio d1d2 is there no net force on particle 0? Express your answer in terms of any or all of the following variables: k,q0,q1,q2.

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Now a) Derive the CDF from the PDF. This will involve anti-differentiation. And

Now although this is silly and quite crude (You have been warned), it is a legit

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Now add a third, negatively charged, particle, whose charge is -q2 (particle 2).

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