A copper wire has a circular cross section with a radius of 5.00 mm. The equatio

Question

A copper wire has a circular cross section with a radius of 5.00 mm. The equation for drift velocity is given below. vd = I/nqA (a) If the wire carries a current of 3.20 A, find the drift speed of the electrons in the wire. (n = 8.46 1028 electrons/m) ______(m/s) (b) All other things being equal, what happens to the drift speed in wires made of metal having a larger number of conduction electrons per atom than copper? Explain. _________________________________________________________________ PLEASE STATE WORK AND ANSWER OR I WILL NOT RATE YOU

Explanation / Answer

a. vd=I/nqA = 3.2 / ( 8.46x10^28 * 1.602*10^-19 * 3.14159 * (5x10^-3)^2)

= 3.0059x10^-6 m/s

b. vd=I/(nqA).

A, q, I are constant according to problem.

Now ne=natom*no. of conduction electrons.

Now natom is constant but no. of cond e increases. So ne increases. Thus vd decreases.

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