an object moves with a constant acceleration 4.00 m/ssquared and over a time int

Question

an object moves with a constant acceleration 4.00 m/ssquared and over a time interval reaches a final velocity of 12.0 m/s. a). If it`s initial velocity is -6.00 m/s, what is it`s displacement during the time interval ? b. What is the distance it travels during this interval?c). If it`s initial velocity is -6.00m/s , what is its displacement during the time interval? d). what is the total distance it travels during the time interval in part c? please help me understand each step , this physics acceleration / velocity crap is already confusing me.

Explanation / Answer

a. If its initial velocity is 5.5 m/s, what is its displacement during the time interval? b. What is the distance it travels during this interval? c. If its initial velocity is -5.5 m/s, what is its displacement during the time interval? d. What is the total distance it travels during the interval in part (c)? Answer a) Vf^2 = Vi^2 + 2ad => 221 = 30.25 + 6.9 d => d = 27.6 m

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