A 60 kg man is in an elevator that is accelerating downward at a rate of 1.4 m/s
ID: 2224574 • Letter: A
Question
A 60 kg man is in an elevator that is accelerating downward at a rate of 1.4 m/s^2. A. What is the true weight of the man? B. what is the net force acting on the man required to produce the acceleration? C What is the force exerted on the man's feet by the floor of the elevator? D. What is the apparent weight of the man in Newtons?(This is the weight that would be read on a bathroon scale if he were standing on it in an accelerating elevator) e. How would your answers to parts b thru d change if the elevator were accelerating upward at 1.4 m/s ^2Explanation / Answer
A 60 kg man is in an elevator that is accelerating downward at a rate of 1.4 m/s^2. A.
What is the true weight of the man?
W = mg = (60 kg)(9.8 m/s ) = 588 N.
B. what is the net force acting on the man required to produce the acceleration?
F = ma = (60 kg)(1.4 m/s ) = 84 N
2
C What is the force exerted on the man's feet by the floor of the elevator?
N=W-ma= m(g-a)=60 (9.8- 1.4)=504 N –UPWARDS
D. What is the apparent weight of the man in Newtons?(This is the weight that would be read on a bathroon scale if he were standing on it in an accelerating elevator)
A scale simply measures the magnitude of whatever force exerted on it. In the case of a man standing
on the scale, it measures the magnitude of the force exerted by the man on the scale. By Newton’s third
law, this force has the same magnitude has the force exerted by the scale on the man (the normal force).
Therefore, the man’s apparent weight is simply the normal force found in part c: N = 504 N.
e. How would your answers to parts b thru d change if the elevator were accelerating upward at 1.4 m/s ^2
N=W+ma= m(g+a)=60 (9.8+1.4)-672 N –UPWARDS
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