Henrietta is going off to her physics class, jogging down the sidewalk at a spee

Question

Henrietta is going off to her physics class, jogging down the sidewalk at a speed of 4.20m/s . Her husband Bruce suddenly realizes that she left in such a hurry that she forgot her lunch of bagels, so he runs to the window of their apartment, which is a height 35.4m above the street level and directly above the sidewalk, to throw them to her. Bruce throws them horizontally at a time 7.00s after Henrietta has passed below the window, and she catches them on the run. You can ignore air resistance. Part A)With what initial speed must Bruce throw the bagels so Henrietta can catch them just before they hit the ground? Part B)Where is Henrietta when she catches the bagels?

Explanation / Answer

So, first we must find how long it will take the bagels to get to the ground. You use the kinematic equation: x=1/2gt^2 So, 35=.5*9.81*t^2 Solve for t >>t=2.67s Now we must find the x position of Henrietta when the bagels are thrown. So Henrietta is 7.5 seconds away plus the 2.67 seconds that the bagels will take to get to her, for a total of 10.17 seconds. Multiply that by her speed to get 42.714 meters. (4.2*10.17) Divide this by the flight time, so (42.714/2.67) gives you 16.00m/s Hope this helps!

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