The moment of inertia of a uniform ring is I (r) = M (r) * R^2 (r), where M (r)

Question

The moment of inertia of a uniform ring is I (r) = M (r) * R^2 (r), where M (r) and R (r) denote the mass and radius of the ring. Similarly, the moment of inertia of a uniform solid disk is I (d) = 1/2 * M (d) * R^2 (d), where M (d) and R (d) represent the mass and radius of the disk. (1) Suppose that M (r) = 0.400 + or - 0.005 kg, while R (r) = 12.0 + or - 0.6 cm, and compute, with error the moment of inertia of this ring. (2) Suppose that M (d) = 0.45 + or - 0.01 kg, while R (d) = 15.0 + or - 0.3 cm. Compute the moment of inertia of this disk (and with error). (3) Compute the ration of these two moments of inertia, along with the error in the ratio

Explanation / Answer

1) .00576 + or - .00003

2) .0050625 + or - .00003

3) ratio = 1.13, error ratio = 1

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.