Julie throws a ball to her friend Sarah. The ball leaves Julie\'s hand a distanc

Question

Julie throws a ball to her friend Sarah. The ball leaves Julie's hand a distance 1.5 meters above the ground with an initial speed of 12.0 m/s at an angle 47.0 degree ; with respect to the horizontal. Sarah catches the ball 1.5 meters above the ground. What is the horizontal component of the ball's velocity when it leaves Julie'hand? m/s What is the vertical component of the ball's velocity when it leaves Julie'hand? m/2 What is the maximum height the ball goes above the ground? m What is the distance between the two girls? m How high above the ground will the ball be when it gets to Julie? (note, the ball may go over Julie's head.) m

Explanation / Answer

a> vx = 12cos47 = 8.18 m/s b> vy = 12sin47 = 8.78 m/s c> h = 8.78^2 / 2*9.8 + 1.5 = 5.43 m d> t = 2*8.78/9.8 = 1.79 s x = 1.79 * 8.18 = 14.66 m this much should help :)

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