object is launched horizontally from a known height. You measure its range (the

Question

object is launched horizontally from a known height. You measure its range (the horizontal distance at which it hits the ground.) Which two equations will allow you to find its initial speed. x = xo + vox t + 1/2 ax t2 vx = vox + ax t vx2 = vox2 + 2 ax (x-xo) y = yo + voy t + 1/2 ay t2 vy = voy + ay t vy2 = voy2 + 2 ay (y-yo) . An object is launched at a known speed and a known angle above the horizontal. Which single equation allows you to find the time it takes to reach the top of its trajectory. x = xo + vox t + 1/2 ax t2 vx = vox + ax t vx2 = vox2 + 2 ax (x-xo) y = yo + voy t + 1/2 ay t2 vy = voy + ay t vy2 = voy2 + 2 ay (y-yo) Check all equations that are needed to derive the following equation: vy2 = voy2 + 2 ay (y-yo) x = xo + vox t + 1/2 ax t2 vx = vox + ax t vx2 = vox2 + 2 ax (x-xo) y = yo + voy t + 1/2 ay t2 vy = voy + ay t

Explanation / Answer

x = x0 + vox t + 1/2 ax t2 and y = y0 + voy t + 1/2 ay t2 will be helpful in 1st problem. vy = voy + ayt. As at highest point vy = 0, and others are known, we can find out t. The equations needed are: y = y0 + v0y t + 1/2 ay t2 and vy = v0y + ayt

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