i need help in 4, 5, and 6 A cannonball is shot (from ground level) with an init
ID: 2227714 • Letter: I
Question
i need help in 4, 5, and 6
A cannonball is shot (from ground level) with an initial horizontal velocity of 34.0 m/s and an initial vertical velocity of 26.0 m/s. What is the initial speed of the cannonball? What is the initial angle theta of the cannonball with respect to the ground? What is the maximum height the cannonball goes above the ground? How far from where it was shot will the cannonball land? What is the speed of the cannonball 4.2 seconds after it was shot? How high above the ground is the cannonball 4.2 seconds after it is shot?Explanation / Answer
a. 42.8 m/s b. theta = tan inverse 26/34 = 37.4 degrees c. h = 24*24/9.8*2 = 29.36 m = max height d. t = 24/9.8 = 2.449 s horizontal distance = vx * t = 88.163 m
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.