A cannon is positioned 300 meters from the base of a cliff. The muzzle makes an

Question

A cannon is positioned 300 meters from the base of a cliff. The muzzle makes an angle of ?=37o with respect to the horizontal, and the initial speed v0 of the projectile right after it leaves the muzzle is 250 m/s. What is the x-component of the initial velocity: v0x? What is the y-component of the initial velocity: v0y? How long after the projectile leaves the cannon's muzzle does the projectile to reach the cliff face? How far up the cliff (as measured from the base of the cliff) does the projectile strike the cliff face?

Explanation / Answer

vx = 199.66 m/s vy = 150.454 m/s t = 300/ vx = 1.5 s h = 215 m

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