I\'m a little confused about this equation v1A1=v2A2 , to solve for A i used pi*

Question

I'm a little confused about this equation v1A1=v2A2 , to solve for A i used pi*r^2 and then I solved for velocity 2 with all other variables known. This seemed pretty straight foward but i get a bad anwser. In the solutions for this problem they just took the diameters and squared it instead of taking the area of of a circle. Can some one please explain this to me, a copy of the problem is listed below. A 1.0-cm-diameter pipe widens to 2.0 , then narrows to 0.5. Liquid flows through the first segment at a speed of 4.0 m/s What is the speed in the second segment?

Explanation / Answer

Yeah v1*A1 = v2*A2 v1* (pi*d1^2) / 4 = v2* (pi*d2^2) / 4 so pi/4 is common to both sides and we cancel those terms v1*d1^2 = v2*d2^2 v2/v1= d1^2/d2^2

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