Two large, parallel, metal plates carry opposite charges of equal magnitude. The

Question

Two large, parallel, metal plates carry opposite charges of equal magnitude. They are separated by a distance of 50.0 mm , and the potential difference between them is 365 V. (PART A): What is the magnitude of the electric field (assumed to be uniform) in the region between the plates? (PART B: What is the magnitude of the force this field exerts on a particle with a charge 2.50 nC? (PART C) Use the results of part B to compute the work done by the field on the particle as it moves from the higher potential plate to the lower. (PART D): Compare the result of part C to the change of the potential energy of the same charge, computed from the electric potential. Thank you so much in advance ! I'll be sure to rate !!

Explanation / Answer

A. E = V/d = 365/0.05 v/m (or N/C) B. F = E*q C. W in J = Vq C. ?PE = -W

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