Two sheets of charge lie parallel to one another and the positive sheet is \"abo

Question

Two sheets of charge lie parallel to one another and the positive sheet is "above" the negative sheet as depicted in the sketch below. The surface charge density of the positive sheet is 19 x 10-6 micro-coulomb/m2, while the surface charge density of the negative sheet is -4.1 x 10-6 micro-coulomb/m2. (Note that due to the sheets not having the same magnitude of charge density, this configuration is NOT a parallel plate capacitor.) How much does the electric potential change due to both sheets from 0.14 meters above the positive sheet to 4.24 meters above the positive sheet in MV (1 x 106 V)? If negative include a negative sign.

Explanation / Answer

Hi, We know the electric field for a charged sheet is given by: E = s/2eoThe force per unit area on sheet I due to sheet II is:F = q

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.