Your friend\'s car has broken down, and you volunteer to push it to the nearest

Question

Your friend's car has broken down, and you volunteer to push it to the nearest repair shop, which is 1.9 km away. You carefully move your car so that the bumpers of the two cars are in contact and then slowly accelerate to a speed of 2.6 m/s over the course of 1 min. (a) If the mass of your friend's car is 1250 kg, what is the normal force between the two bumpers? . N (b) If you then maintain a speed of 2.6 m/s, what is the total time (including the time the cars are accelerating) it takes you to reach the repair shop? s

Explanation / Answer

a.) normal force is Ma a = (v - u)/t = 2.6/60 = .043m/s^2 N = 1250*.043 = 54.17N b.) distance covered during acceleration s = 1/2at^2 = 1/2*.043*60^2 = 77.4m distance left = 1900 - 77.4 = 1822.6m time taken to cover this distance = 1822.6/2.6 = 701s total time = 60 + 701 = 761s

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