A ball is thrown upward. After reaching a maximum height, it continues falling b

Question

A ball is thrown upward. After reaching a maximum height, it continues falling back towards Earth. On the way down, the ball is caught at the same height at which it was thrown upward. Neglect: Air resistance. The acceleration of gravity is 9.8 m/s2 . Its initial vertical speed vo, acceleration of gravity g, and maximum height h1tuix are shown in the figure below. If the time the ball remains in the air is t, calculate the maximum height hmax the ball attained while in the air. If the time (up and down) the ball remains in the air is t, calculate its speed vf when it caught.

Explanation / Answer

2v0/g=t so max ht is v^2/2g=gt^2/8 velocity when it is caught is 2gt/2

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