A student bikes to school by traveling first d_{\ m N} = 1.00\ m {miles} north,

Question

A student bikes to school by traveling first d_{ m N} = 1.00 m {miles} north, then d_{ m W} = 0.600 m {miles} west, and finally d_{ m S} = 0.100 m {miles} south You will now find the same quantity algebraically, without the need to use much geometry. Take the north direction as the positive y direction and east as positive x. The origin is still where the student starts biking. Let d_vec_N be the displacement vector corresponding to the first leg of the student's trip. Express d_vec_N in component form. Express your answer as two numbers separated by a comma (e.g., 1.0,2.0). By convention, the x component is written first

Explanation / Answer

vertical components=1.1-0.2=0.9
horizontal components=.6

.6^2+.9^2=d^2
d=1.081665382639197miles

angle = inv tan (.6/.7)=56.309932474deg west of north or

so .1.08166deg west of north

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