Four point charges are placed on a rectangle as shown in the picture below where

Question

Four point charges are placed on a rectangle as shown in the picture below where q is 6.6 micro-coulombs. The length of the rectangle is 0.55 meters and the its width is 0.27 meters. A fifth point charge of +17.7 micro-coulombs is placed in the center of the rectangle. If the mass of fifth charge was 0.27 kg and started at rest in middle of the rectange and then released, how fast is this charge moving when it is very, very, far away from the other four charges in m/s?

Explanation / Answer

0.5 m v^2 = kq'/r * (q+2q-q-q) ====> v = (2mkqq'/r)^0.5 ---------------------------------------------------------------------------------------------------------------------------------------------------------------- r = (0.27*0.27+0.55*0.55)^0.5 = 0.612699 m ---------------------------------------------------------------------------------------------------------------------------------------------------------------- =====> v = (2*0.27*9e9*6.6e-6*17.7e-6/ 0.612699)^0.5 ---------------------------------------------------------------------------------------------------------------------------------------------------------------- =====> v = 0.963 m/s ----------------------------------------------------------------------------------------------------------------------------------------------------------------

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