second posting-some kid just copied what I posted and wanted a rating for it. A
ID: 2234133 • Letter: S
Question
second posting-some kid just copied what I posted and wanted a rating for it.A sample of gas is compressed to one half its initial volume at a constant pressure of 1.25 x 10^5 P a. During the compression, 100J of work is done on the gas. Determine the final volume of the gas.
So the workbook has the following, but they skipped a step or two, so I'm not following.
W = -P(Vf - Vi)(work is negative because work is done on the gas).
W = -P(Vf - 2Vf) = PVf ** why is pressure not negative?
100J = 1.25 X10^5 Pa * Vf
solve Vf = 8.00 x 10^-4 m^3 or 800 cm^3
I'm just confused as to how neither the 100j of work nore the pressure is negative when it was at the start. This is probably more of an algebra manipulation than physics. Thanks!
Explanation / Answer
work done on the gas is taken as negative in thermodynamics that negative sign is with pressure p
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