Four identical conducting balls, A, B, C, and D are placed on insulating stands.

Question

Four identical conducting balls, A, B, C, and D are placed on insulating stands. Ball A has a net charge of +Q, B has a net charge of -Q and C and D are neutral. Ball C is first brought in contact with ball A and then removed from contact. Then, without discharging ball C, it is brought in contact with ball B and then removed from contact. a.) What is the final charge state of each ball. Explain your reasoning. b.) If the charged balls were brought near but not touching each other two by two, and the balls are held the same distance apart in each case, rank the magnitude of the following forces: Pair One: Fab force of ball A on ball B Fba force of ball B on ball A Pair Two: Fbc force of ball B on ball C Fcb force of ball C on ball B Pair Three:Fad force of ball A on ball D Fda force of ball D on ball A

Explanation / Answer

a) after touching A ball c and A both have charge=Q/2 and after touching c to B both has charge=-Q/4 :: so A=Q/2 ,B=-Q/4,C=-Q/4 :: b) ( Fab=Fba) > (Fad=Fda)=(Fbc=Fcb)

Related Questions

Navigate

• Browse (All)
• Browse F
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.