Consider two point charges located on the x axis: one charge, q1 = -13.5nC , is

Question

Consider two point charges located on the x axis: one charge, q1 = -13.5nC , is located at x1 = -1.650m ; the second charge, q2 = 38.5nC , is at the origin (x=0.0000). Coulomb's law for the magnitude of the force F between two particles with charges Q and Q1 separated by a distance d is: F = K(Q)(Q1)/d^2 WHAT IS THE NET FORCE exerted by these two charges on a third charge q3 = 50.0 nC placed between q1 and q2 at x3 = -1.050 ? Your answer may be positive or negative, depending on the direction of the force. Express your answer numerically in newtons to three significant figures. ** I've already drawn this figure out and solved for Q1 on Q, and again for Q2 on Q...then I added these vectors to get -1.1*10^-6 N, but that's apparently not correct. If someone could help me with the correct answer, that would be great!

Explanation / Answer

Just add the two forces by q1 and q2, sum will be along negative x direction:_________________________ F = 3.258928 x 10^-5 N

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